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Bug 81521

Summary: grep outputs mismatched patterns
Product: [Retired] Red Hat Linux Reporter: Zhao Wu <zhao_wu>
Component: grepAssignee: Tim Waugh <twaugh>
Status: CLOSED NOTABUG QA Contact: Mike McLean <mikem>
Severity: medium Docs Contact:
Priority: high    
Version: 8.0Keywords: Security
Target Milestone: ---   
Target Release: ---   
Hardware: i686   
OS: Linux   
Fixed In Version: Doc Type: Bug Fix
Doc Text:
Story Points: ---
Clone Of: Environment:
Last Closed: 2003-01-10 09:38:18 UTC Type: ---
Regression: --- Mount Type: ---
Documentation: --- CRM:
Verified Versions: Category: ---
oVirt Team: --- RHEL 7.3 requirements from Atomic Host:
Cloudforms Team: --- Target Upstream Version:

Description Zhao Wu 2003-01-10 02:59:03 UTC
From Bugzilla Helper:
User-Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows NT 5.0)

Description of problem:
When I use regular expression in grep, it outputs lines which do not contain 
the specified patterns.

Version-Release number of selected component (if applicable):

How reproducible:

Steps to Reproduce:
Just try the following at shell prompt:
echo "foo" |grep "[L-Z]"

Actual Results:  foo

Expected Results:  nothing should be output

Additional info:

At first, I thought it was a case-sensitivity problem, but later I found more 
problems. Note that in the above example, letter 'f' is not even in the list [l-
z]. grep is being constantly used by many scripts and programs, and this bug 
leads to a potential security breach.

Comment 1 Zhao Wu 2003-01-10 03:01:44 UTC
I forgot to mention that this is a new bug in Redhat 8.0. I tried on 7.3 and 
there is no such a bug.

Comment 2 Tim Waugh 2003-01-10 09:38:18 UTC
You forgot to set LC_COLLATE.  See the bash FAQ question E9.

Comment 3 Zhao Wu 2003-01-10 19:38:15 UTC
Thanks for the FAQ info. LC_COLLATE works, but why does "foo" match "[L-Z]" 
even though 'f' is not in "lLmMnN...zZ"? Isn't that a bug?

Comment 4 Tim Waugh 2003-01-10 22:54:13 UTC
Because 'o' is.